Q:

Hannah was preparing to make 'goody bags' for tricker-treaters on Halloween. She had large bags of snack pack candies: one bag held 48 pieces of chocolate, a second held 64 pieces lollipops, and the third held 80 pieces of bubblegum . How many bags can she prepare if she does not want any candy left over. How many of each type will go into the bags?

Accepted Solution

A:
Answer: There are 8 bags she can prepare if she does not want any candy left over.There are 6 pieces of chocolates , 8 pieces of lollipops and 10 pieces of bubblegum into bags.Step-by-step explanation:Since we have given that Number of pieces of chocolate in one bag = 48Number of pieces of lollipops in second bag = 64Number of pieces of bubblegum in third bag = 80So, we need a large bag of snack pack candies.So, for Number of bags she can prepare if she does not want any candy left over , we will do "H.C.F. of 48, 64, 80" which is equal to 8.So, Number of bags she need to prepare = 8Number of chocolates in bag would be [tex]\dfrac{48}{8}=6[/tex]Number of lollipops in bag would be [tex]\dfrac{64}{8}=8[/tex]Number of bubblegum in bag would be [tex]\dfrac{80}{8}=10[/tex]Hence, there are 6 pieces of chocolates , 8 pieces of lollipops and 10 pieces of bubblegum in 8 bags.